Exos PC RLC

ok
yallah ndewzo lekhrin

dak limorah nefss dakchi lidert ana aussi howa li 7etiti
Ce

mo3adata tafadoliya andiro
u1+u2+uL=0

so2al 2-2

حسب قانون إضافية التوترات

U1 + U2 + Ul = 0

Ue + Ul= 0

Ul= L. di/dt

i= dq/qt = Ce dUe/dt

di/dt= Ce. d²Ue/dt²

d²Ue/dt² + Ue/LC = 0

q = Ce. Ue

Ue = q/Ce

1/Ce . d²q/dt² + q/LC² = 0

(3

1_3
T0= 2 T

Em هو دور تغير الطاقة T

T0= 4 × 10^-3 s

2_3

T0= 2p racine( LCe )

T0² = 4p² LCe

L= T0² / ( 4p² Ce ) = 0.2 H

wéé
dakchi li lkit
hir s3ib bach nektebha hhh heniti yallah kont kanekteb
b7al dakchi dyal derss

binisba li so2al 3_3 ghadi dirih fi chakl nofsso

mili ikon mon7ana li morssom fi Em li ghadi trismih nti ghadi ikon fi 0 o l3akss sa7i7 ..hada binisba li tamtil dyal Ee

amma Et ghadi ikon cte khat fi Em

dakichi li kayin ..b7al darss

4_3

Et = Em = Ee

Et = 0.5 × Ce Ucm² = 1.2 × 10^-5 J

dawr dyal Em je crois c 3

car rah hadak li guolti hir T sur 2
rah makatemchich l kiyam saliba je crois dakchi likalt lina lprof

Exircice 2

_1

Ee max = 0.5 . C . Um²

1_2 (2

T= 2*12*10^-3 = 24*10^-3 s

2_2

بما أن المكثف مشحون قصويا فإن

Uc max = E

E = 4.7 V

3_2

q = C Uc = 4.7 * 10^-5 C

Eemax = 0.5 * C * Uc² = 1.1 * 10^-4 J

4_2
t1=Tعند

Et= Ee = 0.5*C*Uc² = 2.10^-5 J

5_2

delta Et= delta Et0 - delta Et1 = 9.10^-5 J

pk dawr dyalo howa 3 ...???

3

T0= 2p racine ( LC)

T0² = 4p² LC

L= T0²/ ( 4p² C ) = 1.45 H

ana je vais quitté 3yit
dakchi je cois kan3awdo la leçon c tt
yallah chokran abdou

ah la dsl
rah makritch mzyan tadrijat

hta ana timakn wessalt ..hta ana 3yit

yalah bon8

salu si abdo
re
rah atkherej hadik lewla b q2=2q1
op berhant 3lihha ntalekt men
q1= u1 fois c1
q2= u2 fois c2
et c1= 2c2
o 3ewed biha o radi telka hadik natija liguolt lik

incha alah jaribha ..onchof

merci bcp

ana mafhmtch lach tawa7ad ma3rfch ykhraj U1 w U2? !!!!!!!!!

slt lo9mane...hhhh.. hit hta wahid makhadim 3a9lo mezyane .. ila kona fikarna mezyane kona ghadi nwaslo liha ..